Question

Серная кислота с массой 200 г,содержащий 1,5% примесей прореагировала с гидроксидом натрия.Определите массу образовав шея соли

Answer 1

H2SO4 + 2NaOH = Na2SO4 + 2H2O
Найдем массу примесей в растворе:
m(H2SO4)=200г * 0.015=3г
Найдем массу чистого вещества (H2SO4):
m(H2SO4)=200-3=197г
Найдем количество вещества (H2SO4):
n(H2SO4)=m/M=197г/98г/моль = 2.01 моль
n(H2SO4)=n(Na2SO4)=2.01 моль
Найдем массу соли:
m(Na2SO4)=M*n=142.04*2.01=285.5 г
Ответ: 285.5 г

Answer 2

Calculation of the Mass of the Salt Formed

To determine the mass of the salt formed when sulfuric acid reacts with sodium hydroxide, we need to consider the balanced chemical equation for the reaction. The balanced equation is as follows:

H2SO4 + 2NaOH → Na2SO4 + 2H2O

From the equation, we can see that one mole of sulfuric acid (H2SO4) reacts with two moles of sodium hydroxide (NaOH) to form one mole of sodium sulfate (Na2SO4) and two moles of water (H2O).

Given that the mass of sulfuric acid is 200 g and it contains 1.5% impurities, we can calculate the mass of pure sulfuric acid as follows:

Mass of pure sulfuric acid = Mass of sulfuric acid × (100% - % impurities) Mass of pure sulfuric acid = 200 g × (100% - 1.5%) Mass of pure sulfuric acid = 200 g × 98.5% Mass of pure sulfuric acid = 197 g

Now, we can calculate the number of moles of sulfuric acid using its molar mass. The molar mass of sulfuric acid (H2SO4) is 98 g/mol.

Number of moles of sulfuric acid = Mass of pure sulfuric acid / Molar mass of sulfuric acid Number of moles of sulfuric acid = 197 g / 98 g/mol Number of moles of sulfuric acid = 2 moles

According to the balanced equation, one mole of sulfuric acid reacts with two moles of sodium hydroxide to form one mole of sodium sulfate. Therefore, the number of moles of sodium hydroxide required is also 2 moles.

Now, we can calculate the mass of sodium sulfate formed using its molar mass. The molar mass of sodium sulfate (Na2SO4) is 142 g/mol.

Mass of sodium sulfate formed = Number of moles of sodium sulfate × Molar mass of sodium sulfate Mass of sodium sulfate formed = 2 moles × 142 g/mol Mass of sodium sulfate formed = 284 g

Therefore, the mass of the salt formed (sodium sulfate) is 284 grams.