Question

Здравствуйте! Буду очень признателен за решение) В результате восстановления оксида серебра уксусным альдегидом образовалось 2,7г серебра. Какая масса альдегида была при этом окислена ?

Answer 1

 х г                                                              2,7 г

$CH_3CHO+Ag_2O=CH_3COOH+2Ag$

44 г                                                             216 г

при взаимодействии 44 г альдегида восстанавливается 216 г серебра, а

при  --  //  --  //  --  х г____________________________2,7 г, откуда

х=44*2,7/216=0,55 г 

Answer 2

Calculation of the mass of aldehyde oxidized

To determine the mass of aldehyde that was oxidized in the reaction, we need to use the stoichiometry of the reaction and the given information about the mass of silver formed.

The balanced chemical equation for the reaction between silver oxide and acetaldehyde (an aldehyde) is:

2 Ag2O + CH3CHO -> 4 Ag + CH3COOH

From the equation, we can see that 2 moles of silver oxide react with 1 mole of acetaldehyde to produce 4 moles of silver.

Given that the mass of silver formed is 2.7 grams, we can calculate the number of moles of silver using its molar mass. The molar mass of silver (Ag) is approximately 107.87 g/mol.

Number of moles of silver = mass of silver / molar mass of silver Number of moles of silver = 2.7 g / 107.87 g/mol

Now, since the stoichiometry of the reaction tells us that 2 moles of silver oxide react with 1 mole of acetaldehyde, we can set up a ratio to find the number of moles of acetaldehyde.

2 moles Ag2O : 1 mole CH3CHO

Using the number of moles of silver, we can calculate the number of moles of acetaldehyde:

Number of moles of acetaldehyde = (Number of moles of silver) / 2

Finally, we can calculate the mass of acetaldehyde using its molar mass. The molar mass of acetaldehyde (CH3CHO) is approximately 44.05 g/mol.

Mass of acetaldehyde = (Number of moles of acetaldehyde) * (molar mass of acetaldehyde)

Let's calculate the mass of acetaldehyde:

Number of moles of silver = 2.7 g / 107.87 g/mol = 0.025 moles Number of moles of acetaldehyde = 0.025 moles / 2 = 0.0125 moles Mass of acetaldehyde = 0.0125 moles * 44.05 g/mol = 0.55125 grams

Therefore, the mass of aldehyde that was oxidized in the reaction is approximately 0.55125 grams.