
РЕШИТЕ ЦЕПОЧКУ!! ДАЮ 99 БАЛЛОВ! Хлор этан - этилен ( этен)- этиловый спирт - бутодиен 1,3- над
стрелкой (+Br2) x -над стрелкой + H2) y

Ответы на вопрос

Названия:
X-1,4-дибром бутен-2
У-1,4-дибром бутан



Chain Reaction Solution:
The given chain reaction is as follows:
HCl + ethene (ethylene) → ethyl alcohol (ethanol) + 1,3-butadiene + Br2 (bromine) → x + H2 (hydrogen) → y
To solve this chain reaction, we need to determine the values of x and y.
Let's break down the reaction step by step:
1. HCl + ethene (ethylene) → ethyl alcohol (ethanol) + 1,3-butadiene
This is an addition reaction where HCl adds across the double bond of ethene (ethylene) to form ethyl alcohol (ethanol) and 1,3-butadiene.
2. ethyl alcohol (ethanol) + 1,3-butadiene + Br2 (bromine) → x
This is a bromination reaction where bromine (Br2) adds across the double bond of 1,3-butadiene to form a product, x.
3. x + H2 (hydrogen) → y
This is a hydrogenation reaction where hydrogen (H2) adds across the double bond of x to form a product, y.
To determine the values of x and y, we need to consider the reaction conditions and the products formed.
Based on the given information, we can conclude the following:
- The reaction between HCl and ethene (ethylene) forms ethyl alcohol (ethanol) and 1,3-butadiene. - The reaction between 1,3-butadiene and Br2 (bromine) forms a product, x. - The reaction between x and H2 (hydrogen) forms a product, y.
Unfortunately, without additional information or specific reaction conditions, it is not possible to determine the exact values of x and y.
Please provide more information or specific reaction conditions if you need further assistance with this chain reaction.


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