Question

Обчислити об'єм карбон (IV) оксиду, який можна добути при взаємодії кальцій карбонату масою 10г з розчином хлоридної кислоти масою 50г з масовою часткою речовини 20%.

Answer 1

CaCO3+2HCl=CaCl2+H2O+CO2

n(CaCO3)=m/M

M(CaCO3)=100г/моль

n(CaCO3)=10/100

n(CaCO3)=0,1моль

 

n(HCl)=m/M

m(HCl)=50*0,2=10г

M(HCl)=36,5

n(HCl)=0,273моль

 

HCl - у надлишку, тому разрухунки будемо проводити по кальцій карбонату.

 

n(CaCO3)=n(CO2) за рівнянням реакції

 

V=n*Vm

 

V(CO2)=0,1моль*22,4л/моль

V(CO2)=2,24л

 

Відповідь: можна добути 2,24л вуглекислого газу при взаємодії кальцій карбонату з хлоридною кислотою.

 

Answer 2

Calculating the Volume of Carbon (IV) Oxide

To calculate the volume of carbon (IV) oxide produced in the given reaction, we can use the concept of stoichiometry to determine the amount of carbon (IV) oxide produced from the given masses of calcium carbonate and hydrochloric acid.

First, we need to write the balanced chemical equation for the reaction between calcium carbonate and hydrochloric acid to determine the mole ratio between calcium carbonate and carbon (IV) oxide.

The balanced chemical equation for the reaction is: ``` CaCO3 + 2HCl -> CaCl2 + H2O + CO2 ```

From the balanced equation, we can see that 1 mole of calcium carbonate reacts with 2 moles of hydrochloric acid to produce 1 mole of carbon (IV) oxide.

Calculation Steps

1. Calculate the moles of calcium carbonate (CaCO3): - Given mass of calcium carbonate = 10g - Molar mass of CaCO3 = 40.08 g/mol (Ca) + 12.01 g/mol (C) + 3(16.00 g/mol) (O) = 100.09 g/mol - Moles of CaCO3 = Given mass / Molar mass = 10g / 100.09 g/mol = 0.0999 mol

2. Calculate the moles of hydrochloric acid (HCl): - Given mass of hydrochloric acid = 50g - We need to assume the concentration of the hydrochloric acid to calculate the moles. Without this information, it's not possible to calculate the moles accurately.

3. Determine the limiting reactant: - To determine the limiting reactant, we compare the moles of calcium carbonate and hydrochloric acid using the mole ratio from the balanced chemical equation.

4. Calculate the moles of carbon (IV) oxide (CO2) produced: - Once the limiting reactant is identified, we can use the mole ratio to calculate the moles of carbon (IV) oxide produced.

5. Calculate the volume of carbon (IV) oxide: - Finally, we can use the ideal gas law (PV = nRT) to calculate the volume of carbon (IV) oxide produced, given the conditions of temperature and pressure.

Without the concentration of the hydrochloric acid, it's not possible to accurately calculate the moles of hydrochloric acid and proceed with the stoichiometric calculations. If you have the concentration of the hydrochloric acid, please provide it for a more precise calculation.