Question

Масса 10 моль химически чистого сульфата железа(III)

Answer 1

Я прем не думаю но может быть 600800

Answer 2

Chemical Composition of Iron(III) Sulfate

The chemical formula for iron(III) sulfate is Fe2(SO4)3. This means that each molecule of iron(III) sulfate contains two iron (Fe) atoms and three sulfate (SO4) ions.

The molar mass of iron(III) sulfate can be calculated by adding up the atomic masses of the elements in the compound. The atomic masses are as follows: - Iron (Fe): 55.845 u - Sulfur (S): 32.06 u - Oxygen (O): 16.00 u

Using the atomic masses, the molar mass of iron(III) sulfate can be calculated as follows: Molar mass = (2 * atomic mass of Fe) + (3 * (atomic mass of S + 4 * atomic mass of O)) Molar mass = (2 * 55.845) + (3 * (32.06 + 4 * 16.00)) Molar mass = 2 * 55.845 + 3 * (32.06 + 64.00) Molar mass = 111.69 + 3 * 96.06 Molar mass = 111.69 + 288.18 Molar mass = 399.87 g/mol

Therefore, the molar mass of iron(III) sulfate is 399.87 grams per mole.