Question

Расставьте коэффициенты методом электронного баланса,укажите окислитель и восстановитель.....C+H2SO4--->CO2+H2O+SO2

Answer 1

$C + 2H2SO4 ---> CO2 + 2H2O + 2SO2$

восстановитель             C(0) -----> С(+2)       |    4     |    2    окисление
окислитель                      S(+6) ----> S(+2)      |    2     |    1    восстановление

Answer 2

C+2H2SO4--->CO2+2H2O+2SO2

С-восстановитель, процесс окисления

Н2SO4 - окислитель, процесс восстановления

Answer 3

Balancing the Equation using the Method of Electron Balance

To balance the chemical equation C + H2SO4 -> CO2 + H2O + SO2 using the method of electron balance, we need to ensure that the number of electrons gained in the reduction half-reaction is equal to the number of electrons lost in the oxidation half-reaction.

Let's break down the equation into half-reactions:

Oxidation Half-Reaction: C -> CO2

In this half-reaction, carbon (C) is oxidized from an oxidation state of 0 to +4 in CO2. To balance the carbon atoms, we need to add a coefficient of 1 in front of CO2.

Reduction Half-Reaction: H2SO4 -> H2O + SO2

In this half-reaction, sulfur (S) is reduced from an oxidation state of +6 in H2SO4 to +4 in SO2. To balance the sulfur atoms, we need to add a coefficient of 1 in front of SO2.

Now, let's balance the hydrogen (H) and oxygen (O) atoms:

Balancing Hydrogen Atoms: On the left side, we have 2 hydrogen atoms in H2SO4, and on the right side, we have 2 hydrogen atoms in H2O. The hydrogen atoms are already balanced.

Balancing Oxygen Atoms: On the left side, we have 4 oxygen atoms in H2SO4, and on the right side, we have 2 oxygen atoms in CO2 and 1 oxygen atom in H2O. To balance the oxygen atoms, we need to add a coefficient of 2 in front of H2O.

Now, let's summarize the balanced equation:

C + H2SO4 -> CO2 + 2H2O + SO2

Identifying the Oxidizing and Reducing Agents

In the balanced equation C + H2SO4 -> CO2 + 2H2O + SO2, we can identify the oxidizing and reducing agents based on the changes in oxidation states.

The oxidizing agent is the species that gets reduced, while the reducing agent is the species that gets oxidized.

In this equation: - Carbon (C) is oxidized from an oxidation state of 0 to +4 in CO2. Therefore, carbon is the reducing agent. - Sulfur (S) is reduced from an oxidation state of +6 in H2SO4 to +4 in SO2. Therefore, sulfur is the oxidizing agent.

Summary

The balanced equation using the method of electron balance for the reaction C + H2SO4 -> CO2 + 2H2O + SO2 is:

C + H2SO4 -> CO2 + 2H2O + SO2

In this equation, carbon (C) is the reducing agent, and sulfur (S) is the oxidizing agent.