Question

Гидрид кальция растворили в воде. Выделившийся газ пропустили над раскалённым порошком оксида меди (II). Образовавшееся твёрдое вещество растворили при нагревании в концентрированной серной кислоте. Полученную соль выделили и добавили к раствору иодида калия. Напишите уравнения четырёх описанных реакций.

Answer 1

CaH2+2H2O=Ca(OH)2+H2
CuO+H2=H2O+Cu
Cu+2H2SO4=CuSO4+SO2+2H2O
2CuSO4+4KI=I2+2K2SO4+2CuI

Answer 2

Reaction 1: Dissolving Calcium Hydride in Water

When calcium hydride (CaH2) is dissolved in water (H2O), it reacts to produce hydrogen gas (H2) and calcium hydroxide (Ca(OH)2).

The balanced chemical equation for this reaction is: CaH2 + 2H2O -> 2H2 + Ca(OH)2

Reaction 2: Passing the Evolved Gas over Heated Copper(II) Oxide Powder

The hydrogen gas (H2) evolved from the reaction in the previous step is passed over heated copper(II) oxide (CuO) powder. This reaction results in the formation of water (H2O) and copper (Cu).

The balanced chemical equation for this reaction is: CuO + H2 -> H2O + Cu

Reaction 3: Dissolving the Formed Solid Substance in Concentrated Sulfuric Acid

The solid substance formed in the previous step is dissolved by heating it with concentrated sulfuric acid (H2SO4). This reaction produces sulfur dioxide gas (SO2), water (H2O), and copper sulfate (CuSO4).

The balanced chemical equation for this reaction is: Cu + 2H2SO4 -> CuSO4 + SO2 + 2H2O

Reaction 4: Adding the Obtained Salt to Potassium Iodide Solution

The copper sulfate (CuSO4) obtained from the previous step is added to a solution of potassium iodide (KI). This reaction leads to the formation of copper(II) iodide (CuI2) and potassium sulfate (K2SO4).

The balanced chemical equation for this reaction is: CuSO4 + 2KI -> CuI2 + K2SO4

Please note that the specific conditions and concentrations of the reactants may affect the reaction outcomes.