Question

NH4OH+Pb(NO3)2= Ионное пожалуйста)

Answer 1

Решение во вложении :)

Answer 2

Reaction: NH4OH + Pb(NO3)2

When NH4OH (ammonium hydroxide) reacts with Pb(NO3)2 (lead(II) nitrate), an ionic reaction occurs. The reaction can be represented as follows:

NH4OH + Pb(NO3)2 → NH4NO3 + Pb(OH)2

The products of this reaction are ammonium nitrate (NH4NO3) and lead(II) hydroxide (Pb(OH)2).

Explanation:

In this reaction, ammonium hydroxide (NH4OH) is a weak base, while lead(II) nitrate (Pb(NO3)2) is a salt. When they react, the ammonium ion (NH4+) from NH4OH combines with the nitrate ion (NO3-) from Pb(NO3)2 to form ammonium nitrate (NH4NO3). The hydroxide ion (OH-) from NH4OH combines with the lead(II) ion (Pb2+) from Pb(NO3)2 to form lead(II) hydroxide (Pb(OH)2).

The reaction can be understood in terms of the exchange of ions. The ammonium ion (NH4+) and the nitrate ion (NO3-) switch partners, resulting in the formation of ammonium nitrate (NH4NO3). Similarly, the hydroxide ion (OH-) and the lead(II) ion (Pb2+) switch partners, resulting in the formation of lead(II) hydroxide (Pb(OH)2).

Summary:

In summary, when ammonium hydroxide (NH4OH) reacts with lead(II) nitrate (Pb(NO3)2), the products formed are ammonium nitrate (NH4NO3) and lead(II) hydroxide (Pb(OH)2)