Question

Составит молекулярные и ионные уравнения реакций взаимодействия в растворах между AlCl3 иKOH

Answer 1

AlCl3+3KOH=Al(OH)3 + 3KCl
Al(OH)3 + KOH = K[Al(OH)4]

Al(3+) + 3OH(-) = Al(OH)3
Al(OH)3 + OH(-) = [Al(OH)4](-)

Answer 2

Molecular Equation:

The molecular equation for the reaction between AlCl3 and KOH in solution is as follows:

AlCl3 + 3KOH → Al(OH)3 + 3KCl

Ionic Equation:

To write the ionic equation, we need to break down the reactants and products into their respective ions:

Reactants: - AlCl3 dissociates into Al3+ and Cl- ions. - KOH dissociates into K+ and OH- ions.

Products: - Al(OH)3 forms from the combination of Al3+ and OH- ions. - KCl forms from the combination of K+ and Cl- ions.

Therefore, the ionic equation for the reaction is:

Al3+ + 3OH- + 3K+ + 3Cl- → Al(OH)3 + 3K+ + 3Cl-

Net Ionic Equation:

In the net ionic equation, we eliminate the spectator ions (ions that appear on both sides of the equation) to focus on the species directly involved in the reaction.

In this case, the K+ and Cl- ions are spectator ions because they appear on both sides of the equation. Therefore, we can eliminate them from the equation:

Al3+ + 3OH- → Al(OH)3 This is the net ionic equation for the reaction between AlCl3 and KOH in solution.

Please note that the information provided is based on the search results and may not be exhaustive.