
Fe(OH)2+Na2SO4 розписати


Ответы на вопрос







Reaction: Fe(OH)2 + Na2SO4
The reaction between Fe(OH)2 (iron(II) hydroxide) and Na2SO4 (sodium sulfate) can be represented as follows:
Fe(OH)2 + Na2SO4 -> FeSO4 + 2NaOH
In this reaction, iron(II) hydroxide reacts with sodium sulfate to form iron(II) sulfate and sodium hydroxide.
Balancing the Equation
To balance the equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation. Let's balance the equation step by step:
1. Balance the iron atoms: There is 1 iron atom on the left side and 1 iron atom on the right side, so the iron atoms are already balanced.
2. Balance the hydrogen atoms: There are 2 hydrogen atoms in Fe(OH)2 and 2 hydrogen atoms in 2NaOH on the right side. Therefore, the hydrogen atoms are already balanced.
3. Balance the oxygen atoms: There are 4 oxygen atoms in 2NaOH on the right side. To balance this, we need 4 oxygen atoms on the left side. We can achieve this by adding 2 water molecules (H2O) to the left side of the equation:
Fe(OH)2 + Na2SO4 -> FeSO4 + 2NaOH + 2H2O
Now, the equation is balanced with respect to the number of atoms of each element.
Conclusion
The balanced equation for the reaction between Fe(OH)2 and Na2SO4 is:
Fe(OH)2 + Na2SO4 -> FeSO4 + 2NaOH + 2H2O
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