Question

1)Допишите уравнение, расставьте где нужно коэффициенты, определите тип реакции:Fe2O3+HCI=H2O+?Mg+H2SO4=?+H2ZnO=?+?Ba+?=BaH22)Запишите формулами и определите тип реакции и расставите коэффициентыГидроксид алюминия=оксид алюминия+ водахлорид кальция+нитрат серебра=хлорид серебра+нитрат кальциягидроксид калия+серная кислота=сульфат калия+вода

Answer 1

в последнем уравнении тоже обмен

Answer 2

1.Fe2O3+6HCl=3H2O+2FeCl3

Mg+2H2SO4=Mg(SO4)2+2H22ZnO+2Zn+O2

Ba+H2=BaH2

 2.2Al(OH)3=Al2O3+3H20-реакция разложения

2CaCl2+2AgNO3=2AgCl+Ca(NO3)2-реакция обмена

2KOH+H2SO4=K2SO4+2H2O-реакция замещения

Answer 3

1) Let's solve the equations one by one and determine the type of reaction for each:

a) Fe2O3 + HCl = H2O + ?Mg + H2SO4 = ?H2ZnO = ?Ba + ? = BaH2

For the first equation, Fe2O3 + HCl = H2O + ? we have iron (III) oxide reacting with hydrochloric acid. To balance the equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation.

Fe2O3 + 6HCl = 3H2O + 2FeCl3

The reaction type is a redox reaction, specifically a displacement reaction.

For the second equation, Mg + H2SO4 = ? we have magnesium reacting with sulfuric acid. Again, we need to balance the equation:

Mg + H2SO4 = MgSO4 + H2

The reaction type is a single displacement reaction.

For the third equation, H2ZnO = ? we have an incomplete equation. We need to know the reactant(s) to balance it.

For the fourth equation, Ba + ? = BaH2 we have barium reacting to form barium hydride. Again, we need to know the reactant(s) to balance the equation.

2) Let's write the formulas, determine the type of reaction, and balance the equations:

a) Hydroxide of aluminum = Aluminum oxide + water

Al(OH)3 = Al2O3 + H2O

The reaction type is a decomposition reaction.

b) Calcium chloride + silver nitrate = Silver chloride + calcium nitrate

CaCl2 + 2AgNO3 = 2AgCl + Ca(NO3)2

The reaction type is a double displacement reaction.

c) Potassium hydroxide + sulfuric acid = Potassium sulfate + water

2KOH + H2SO4 = K2SO4 + 2H2O

The reaction type is a double displacement reaction.

I hope this helps! Let me know if you have any further questions.