Question

Расставить коэффициенты методом электронного баланса,указать окислитель,восстановитель,процессы окисления и восстановления Cr+HNO3->Cr(NO3)3+H2O+H2O

Answer 1

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Answer 2

Balancing the Equation

To balance the equation using the method of electronic balancing, we need to ensure that the number of atoms of each element is the same on both sides of the equation.

The given equation is: Cr + HNO3 -> Cr(NO3)3 + H2O + H2O

Let's balance the equation step by step:

1. Balance the atoms other than hydrogen and oxygen: - The chromium (Cr) atom is already balanced on both sides. - The nitrogen (N) atom is already balanced on both sides. - The oxygen (O) atom is already balanced on both sides.

2. Balance the hydrogen (H) atoms: - There are 3 hydrogen atoms on the left side (HNO3) and 4 hydrogen atoms on the right side (H2O + H2O). - To balance the hydrogen atoms, we need to add 1 more HNO3 on the left side.

The balanced equation becomes: Cr + 2 HNO3 -> Cr(NO3)3 + H2O + H2O

3. Verify the balance of all atoms: - The chromium (Cr) atom is balanced with 1 on both sides. - The nitrogen (N) atom is balanced with 3 on both sides. - The oxygen (O) atom is balanced with 9 on both sides. - The hydrogen (H) atom is balanced with 6 on both sides.

Identification of Oxidizing and Reducing Agents

To identify the oxidizing and reducing agents, we need to determine the changes in oxidation states of the elements involved in the reaction.

In the given equation: Cr + 2 HNO3 -> Cr(NO3)3 + H2O + H2O

- The oxidation state of chromium (Cr) changes from 0 to +3 in Cr(NO3)3. Chromium is oxidized and acts as the reducing agent. - The oxidation state of nitrogen (N) changes from +5 to +3 in Cr(NO3)3. Nitrogen is reduced and acts as the oxidizing agent.

Therefore, in the given equation: - The oxidizing agent is nitric acid (HNO3). - The reducing agent is chromium (Cr).

Summary of the Processes

In the given equation: Cr + 2 HNO3 -> Cr(NO3)3 + H2O + H2O

- The process of oxidation occurs to chromium (Cr), which changes its oxidation state from 0 to +3. - The process of reduction occurs to nitrogen (N), which changes its oxidation state from +5 to +3.

Please note that the equation you provided has duplicate products (H2O + H2O). It is unusual to have duplicate products in a balanced chemical equation. If you have any further questions, feel free to ask!