Question

Вычислить процентное содержание углерода и водорода в глюкозе!помогите!

Answer 1

C6H12O6-глюкоза
M(C6H12O6) = 180г/моль
W(C)= 6M(C)/M(C6H12O6) * 100 = 40%
W(H)=12M(H)/M(C6H12O6) * 100 = 6,7%

Answer 2

Calculation of the Percentage of Carbon and Hydrogen in Glucose

To calculate the percentage of carbon and hydrogen in glucose, we need to know the molecular formula of glucose, which is C6H12O6. From this formula, we can determine the number of carbon and hydrogen atoms present in one molecule of glucose.

- Carbon (C): Glucose contains 6 carbon atoms. - Hydrogen (H): Glucose contains 12 hydrogen atoms.

To calculate the percentage of each element, we need to divide the number of atoms of that element by the total number of atoms in one molecule of glucose and then multiply by 100.

Percentage of Carbon in Glucose: Number of carbon atoms in glucose = 6 Total number of atoms in glucose = 6 (carbon) + 12 (hydrogen) + 6 (oxygen) = 24

Percentage of carbon = (Number of carbon atoms / Total number of atoms) * 100 Percentage of carbon = (6 / 24) * 100 = 25%

Percentage of Hydrogen in Glucose: Number of hydrogen atoms in glucose = 12 Total number of atoms in glucose = 6 (carbon) + 12 (hydrogen) + 6 (oxygen) = 24

Percentage of hydrogen = (Number of hydrogen atoms / Total number of atoms) * 100 Percentage of hydrogen = (12 / 24) * 100 = 50%

Therefore, the percentage of carbon in glucose is 25% and the percentage of hydrogen in glucose is 50%.

Please note that the above calculations are based on the molecular formula of glucose and assume that the glucose molecule is in its standard form.