Question

1. Этот элемент (Э) расположен во II группе, во 2 периоде. Вода на него никак не действует, а вот с сильными кислотами, например, с серной кислотой, он легко реагирует . Оксид и гидроксид этого элемента взаимодействуют и с кислотами и с сильными щелочами. Так, при взаимодействии с гидроксидом натрия, образуется соль Na2ЭО2. Напишите формулу кислотного остатка. Назовите эту соль. Напишите характеристику элемента по плану и уравнения всех реакций, упомянутых в тексте.

Answer 1

Be + H₂SO₄ = BeSO₄ + H₂↑

BeO + 2HNO₃ = Be(NO₃)₂ + H₂O

Be(OH)₂ + 2HCl = BeCl₂ + 2H₂O

BeO + 2NaOH (сплавл., t) = Na₂BeO₂ + H₂O↑

Be(OH)₂ + 2NaOH (сплавл., t) = Na₂BeO₂ + 2H₂O↑
                                                    бериллат
                                                     натрия

BeO + 2NaOH(раствор) +H₂O = Na₂[Be(OH)₄]

Be(OH)₂ + 2NaOH(раствор) = Na₂[Be(OH)₄]
                                                 тетрагидроксобериллат натрия

Answer 2

Element in Group II, Period 2

The element mentioned in the text is located in Group II and Period 2 of the periodic table. It is not affected by water, but it readily reacts with strong acids, such as sulfuric acid.

Acidic Residue Formula and Salt Name

The acidic residue of this element can be determined by examining the reaction with sodium hydroxide (NaOH), which forms the salt Na2EO2. From this information, we can deduce that the formula of the acidic residue is EO2. However, the specific name of the salt formed cannot be determined without knowing the identity of the element (represented by E in the text).

Characteristics of the Element

Unfortunately, the text does not provide enough information to determine the specific characteristics of the element. To accurately describe the element, we would need additional details such as its atomic number, atomic mass, electron configuration, and other properties. Without this information, it is not possible to provide a comprehensive characterization of the element mentioned in the text.

Reactions Mentioned in the Text

The text mentions several reactions involving the element:

1. Reaction with strong acids: The element readily reacts with strong acids, such as sulfuric acid (H2SO4). 2. Reaction with sodium hydroxide: When the element reacts with sodium hydroxide (NaOH), it forms the salt Na2EO2.

Unfortunately, the text does not provide any additional reactions or details about the element. If you have any specific questions or need further information, please let me know!