Question

Помогите с химией, срочно)) Составьте уравнение реакций: 1. NaCl-NaOH-Cu(OH)2-CuSO4-Cu-CuCl 2. Cu-CuCl2-Cu(NO3)2-CuO-CuSO4-CuCl2 3. NaCl-Na-NaOH-Al(OH)3-AlCl3-AgCl Пожалуйста, помогиитееее

Answer 1

Приветствую
               ₁             ₂                ₃               ₄         ₅
A. NaCl  → NaOH  → Cu(OH)₂ → CuSO₄ → Cu → CuCl₂ ( опечатка у вас )
1. 2NaCl + 2H₂O = 2NaOH + Cl₂ + H₂↑
2. 2NaOH + CuSO₄ = Na₂SO₄ + Cu(OH)₂↓
3. Cu(OH)₂ + H₂SO₄ = CuSO₄ + 2H₂O
4. CuSO₄ + Fe = Cu + FeSO₄
5. Cu + Cl₂ = CuCl₂
             ₁             ₂               ₃             ₄            ₅
Б. Сu → CuCl₂ → Cu(NO₃)₂ → CuO → CusO₄ → CuCl₂
1. Cu + Cl₂ = CuCl₂
2. CuCl₂ + 2AgNO₃ = Cu(NO₃)₂ + 2AgCl↓
                  t
3. Cu(NO₃)₂ = CuO + 2NO₂ + O₂
4. CuO + SO₃ = CuSO₄
5. CuSO₄ + BaCl₂ = CuCl₂ + BaSO₄↓
              ₁         ₂             ₃               ₄           ₅
B. NaCl → Na → NaOH → Al(OH)₃ → AlCl₃ → AgCl
1. 2NaCl = 2Na + Cl₂ ( электролиз )
2. 2Na + 2H₂O = 2NaOH + H₂↑
3. 3NaOH + AlCl₃ = Al(OH)₃↓+ 3NaCl
4. Al(OH)₃ + 3HCl = AlCl₃ + 3H₂O
5. AgNO₃ + AlCl₃ = AgCl↓ + Al(NO₃)₃

Answer 2

1. NaCl - NaOH - Cu(OH)2 - CuSO4 - Cu - CuCl

The balanced equation for the given reaction sequence is as follows:

2 NaCl + 2 NaOH + Cu(OH)2 → CuSO4 + 2 H2O + 2 NaCl + 2 NaOH + Cu

Explanation: - The reaction starts with sodium chloride (NaCl) and sodium hydroxide (NaOH). - Sodium hydroxide reacts with copper(II) hydroxide (Cu(OH)2) to form copper(II) sulfate (CuSO4) and water (H2O). - The copper(II) sulfate then undergoes a displacement reaction with sodium chloride and sodium hydroxide, resulting in the formation of copper (Cu). - Finally, copper reacts with excess sodium chloride to form copper(I) chloride (CuCl).

2. Cu - CuCl2 - Cu(NO3)2 - CuO - CuSO4 - CuCl2

The balanced equation for the given reaction sequence is as follows:

2 Cu + 2 CuCl2 + 4 HNO3 → 2 Cu(NO3)2 + 2 CuO + 4 HCl 2 CuO + 2 H2SO4 → 2 CuSO4 + 2 H2O CuSO4 + 2 NaCl → CuCl2 + Na2SO4

Explanation: - The reaction starts with copper (Cu) and copper(II) chloride (CuCl2). - Copper reacts with copper(II) chloride to form copper(I) chloride (CuCl) and copper(II) nitrate (Cu(NO3)2) in the presence of nitric acid (HNO3). - Copper(I) chloride then reacts with copper(II) oxide (CuO) in the presence of sulfuric acid (H2SO4) to form copper(II) sulfate (CuSO4) and water (H2O). - Finally, copper(II) sulfate reacts with sodium chloride (NaCl) to form copper(II) chloride (CuCl2) and sodium sulfate (Na2SO4).

3. NaCl - Na - NaOH - Al(OH)3 - AlCl3 - AgCl

The balanced equation for the given reaction sequence is as follows:

3 NaCl + 3 Na + 3 H2O → 3 NaOH + 3 H2 + 3 Cl2 2 Al + 6 H2O → 2 Al(OH)3 + 3 H2 2 Al(OH)3 + 6 HCl → 2 AlCl3 + 6 H2O 2 AlCl3 + 6 NaCl → 2 AlCl3 + 6 NaCl

Explanation: - The reaction starts with sodium chloride (NaCl) and sodium (Na). - Sodium reacts with water (H2O) to form sodium hydroxide (NaOH) and hydrogen gas (H2). - Aluminum (Al) reacts with water to form aluminum hydroxide (Al(OH)3) and hydrogen gas. - Aluminum hydroxide reacts with hydrochloric acid (HCl) to form aluminum chloride (AlCl3) and water. - Finally, aluminum chloride reacts with excess sodium chloride to form aluminum chloride and sodium chloride.

Please note that the given reaction sequence may not be complete or accurate. It is always recommended to consult reliable sources or textbooks for accurate and complete information on chemical reactions.