Question

Какой объем при нормальных условиях займут 24,08*10^23молекул кислорода?

Answer 1

N(авогадро)=6.02*10^23 - это значит, что в 1 моль вещества находится такое кол-во молекул. значит можно найти количество моль:
n=N/N(a)=(24,08*10^23)/(6.02*10^23)=0.4моль
V(H2)=Vm(1 моль газа занимает объем 22.4л) *n=22.4*0.4=8,96л

Answer 2

Calculating the Volume of 24.08*10^23 Oxygen Molecules at Standard Conditions

To calculate the volume occupied by 24.08*10^23 molecules of oxygen at standard conditions, we can use the ideal gas law, which states that PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature.

Step 1: Calculate the Number of Moles Using Avogadro's number (6.02*10^23), we can calculate the number of moles of oxygen molecules. n = N/Na, where N is the number of molecules and Na is Avogadro's number. n = 24.08*10^23 / 6.02*10^23 = 4.

Step 2: Calculate the Volume Now that we have the number of moles, we can calculate the volume using the ideal gas law. V = nRT/P, where R is the gas constant and T is the temperature at standard conditions. Given that the temperature at standard conditions is 300 K and the pressure is 1 atm, we can use the value of the gas constant R = 0.0821 L·atm/(K·mol). V = (4 * 0.0821 * 300) / 1 = 9.84 L.

Therefore, 24.08*10^23 molecules of oxygen will occupy approximately 9.84 liters at standard conditions.

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