Question

Водный раствор BaCl2 реагирует с веществом , формула которого: а)NaSO4 б)Cu в)CaCO3 г)KNO3

Answer 1

BaCl2 +Na2SO4=BaSO4 +2NaCl    ответ а)

Answer 2

Хлорид бария прореагирует с сульфатом натрия. реакция:
[tex]BaCl2+Na2SO4=2NaCl+BaSO4 (осадок)

Ответ: А

Answer 3

Reaction of BaCl2 with Different Substances

When BaCl2 reacts with different substances, the following reactions occur:

а) NaSO4: The reaction between BaCl2 and NaSO4 results in the formation of BaSO4 and NaCl. ``` BaCl2 + Na2SO4 → BaSO4 + 2NaCl ``` This reaction is a double displacement reaction, where the cations and anions of the two compounds switch places to form two new compounds .

б) Cu: Barium chloride does not react with copper (Cu) under normal conditions. Therefore, no reaction occurs between BaCl2 and Cu .

в) CaCO3: When BaCl2 reacts with CaCO3, no reaction occurs under normal conditions. Barium chloride and calcium carbonate do not undergo a chemical reaction .

г) KNO3: Barium chloride does not react with potassium nitrate (KNO3) under normal conditions. Therefore, no reaction occurs between BaCl2 and KNO3 .

In summary, the reactions of BaCl2 with the given substances are as follows: - а) NaSO4: BaCl2 + Na2SO4 → BaSO4 + 2NaCl - б) Cu: No reaction - в) CaCO3: No reaction - г) KNO3: No reaction