Question

Вычислите массу соли, полученой при полном взаимодействие 48 г магния с хлором

Answer 1

Mg+cl2=mgcl2
48/24=2моль
2×95=190г соли

Answer 2

Calculating the Mass of Salt Produced from the Reaction of Magnesium with Chlorine

To calculate the mass of salt produced when 48g of magnesium reacts with chlorine, we need to determine the chemical equation for the reaction and then use stoichiometry to find the mass of the salt produced.

The balanced chemical equation for the reaction between magnesium and chlorine is: Mg + Cl2 → MgCl2

From the balanced chemical equation, we can see that 1 mole of magnesium reacts with 1 mole of chlorine to produce 1 mole of magnesium chloride.

The molar mass of magnesium (Mg) is approximately 24.305 g/mol, and the molar mass of chlorine (Cl2) is approximately 70.906 g/mol.

Using this information, we can calculate the mass of magnesium chloride produced.

Calculation

1. Calculate the moles of magnesium: - Moles of Mg = Mass of Mg / Molar mass of Mg - Moles of Mg = 48g / 24.305 g/mol - Moles of Mg = 1.974 moles

2. Since the reaction is 1:1 between magnesium and chlorine, the moles of chlorine required will be the same as the moles of magnesium.

3. Calculate the mass of magnesium chloride produced: - Mass of MgCl2 = Moles of MgCl2 * Molar mass of MgCl2 - Molar mass of MgCl2 = Molar mass of Mg + 2 * Molar mass of Cl - Molar mass of MgCl2 = 24.305 g/mol + 2 * 35.453 g/mol - Molar mass of MgCl2 = 95.211 g/mol - Mass of MgCl2 = 1.974 moles * 95.211 g/mol - Mass of MgCl2 = 187.7g

Therefore, the mass of salt (magnesium chloride) produced when 48g of magnesium reacts with chlorine is approximately 187.7 grams.