Question

найдите молекулярную формулу алкена, если известно, что при взаимодействии 1.008 л его с хлором образуется 5.09 г дихлорппроизводного

Answer 1

CnH2n+Cl2----->CnH2nCl2

n(CnH2n)=V(CnH2n)/Vm=1,008/22,4=0,045(моль)

По уравнению реакции химическое количество алкена и дихлорпроизводного равны, поэтому n(CnH2n)=n(CnH2nCl2)=0,045 моль

M(CnH2nCl2)=m/n=5,09/0,045=113(моль)

Узнаем молярную массу алкена, отняв от молярной массы дихлопроизводного массу двух атомов хлора:

M(CnH2n)=M(CnH2nCl2)-M(Cl2)=113-35,5*2=113-71=42(моль)

Методом подбора узнаём, что получился алкен C3H6.

Проверяем его молярную массу: M(C3H6)=12*3+6=36+6=42(моль)

Значит, C3H6 - искомый алкен.

 

Answer 2

Molecular Formula of Alkene

To find the molecular formula of the alkene, we can start by calculating the molar mass of the alkene and the dihaloproduct. Then, we can use the given information about the reaction to determine the molecular formula of the alkene.

First, let's calculate the molar mass of the dihaloproduct using the given information.

Given: - Volume of alkene = 1.008 L - Mass of dihaloproduct = 5.09 g

We can use the relationship between volume, moles, and molar mass to find the molar mass of the dihaloproduct. The molar mass of the dihaloproduct can be calculated using the formula:

Molar mass = (mass / moles)

To find the moles of the dihaloproduct, we can use the ideal gas law equation:

n = PV / RT

Where: - P = pressure (assuming standard pressure) - V = volume of the gas - n = moles of the gas - R = ideal gas constant - T = temperature (assuming standard temperature)

After finding the moles of the dihaloproduct, we can calculate its molar mass.

Next, we can use the molar mass of the dihaloproduct to determine the molar mass of the alkene and then deduce its molecular formula.

Let's proceed with the calculations and determine the molecular formula of the alkene based on the given information.