Question

Какой углерод получиться при действии спиртового раствора щелочи на 2-бром-2-метилбутан? Назовите его. Напишите для него реакцию с HCl и H2SO4

Answer 1

образуется 2-метилбутен-2 СН3-СH=C(CH3)-CH3

СН3-СH2-CBr(CH3)-CH3 +KOH = СН3-СH=C(CH3)-CH3 +KBr+H2O

СН3-СH=C(CH3)-CH3 + HCl = СН3-СH2-CCl(CH3)-CH3 ( 2-хлор-2-метилбутан)

СН3-СH=C(CH3)-CH3 + H2SO4 = СН3-СH2-C(SO3H)(CH3)-CH3
( 2-метил-2-бутансульфокислота)

Answer 2

Reaction of 2-Bromo-2-Methylpropane with Alcoholic Potassium Hydroxide

When 2-bromo-2-methylpropane (also known as tert-butyl bromide) reacts with alcoholic potassium hydroxide, it undergoes an elimination reaction to form 2-methylpropene as the major product.

The reaction can be represented as follows: ``` (CH3)3CBr + KOH → (CH3)2C=CH2 + KBr + H2O ``` This reaction is an example of an E2 (bimolecular elimination) reaction, where the alkyl halide reacts with a strong base to form an alkene.

Reactions of 2-Methylpropene with HCl and H2SO4

2-Methylpropene can undergo addition reactions with HCl and H2SO4.

1. Reaction with HCl: - In the presence of HCl, 2-methylpropene undergoes an addition reaction to form 2-chloro-2-methylpropane. - The reaction can be represented as: ``` (CH3)2C=CH2 + HCl → (CH3)2C(Cl)-CH3 ```

2. Reaction with H2SO4: - In the presence of concentrated sulfuric acid (H2SO4), 2-methylpropene undergoes an addition reaction to form 2-methyl-2-propanol. - The reaction can be represented as: ``` (CH3)2C=CH2 + H2SO4 → (CH3)3COH ```

These reactions demonstrate the versatility of 2-methylpropene in undergoing addition reactions with different reagents.