Question

. Сколько граммов этилена должно вступить в реакцию с водородом, чтобы образовалось 5 г/моль этана.

Answer 1

C2H4 +H2= C2H6
n(C2H6)= m\M=5\30=0,17 моль
nC2H6=nC2H4=0,17 моль
mC2H4 =M*n=28*0,17=4,7г

Answer 2

Calculating the Amount of Ethylene Needed to Produce 5g/mol of Ethane

To calculate the amount of ethylene (C2H4) needed to produce 5g/mol of ethane (C2H6) in the reaction with hydrogen (H2), we can use the balanced chemical equation for the reaction between ethylene and hydrogen to form ethane:

C2H4 + H2 → C2H6

The molar mass of ethylene (C2H4) is 28.05 g/mol, and the molar mass of ethane (C2H6) is 30.07 g/mol.

To find the amount of ethylene needed to produce 5g/mol of ethane, we can use the stoichiometry of the reaction. According to the balanced chemical equation, 1 mole of ethylene reacts with 1 mole of hydrogen to produce 1 mole of ethane.

Using the molar masses of ethylene and ethane, we can calculate the amount of ethylene needed as follows:

Amount of ethylene = (Molar mass of ethane / Molar mass of ethylene) * 5g

Amount of ethylene = (30.07g/mol / 28.05g/mol) * 5g

Amount of ethylene ≈ 5.36g

Therefore, approximately 5.36 grams of ethylene should react with hydrogen to produce 5g/mol of ethane.