Question

Помогите сделать ОВР, пожалуйста! Cu + HNO3 = Cu(NO3)2 + NO + H2O И подробно!

Answer 1

3Cu + 8HNO3 = 3Cu(NO3)2 + 2NO + 4H2O
Составляем баланс
$\left. \begin{array}{r} \mathrm{Cu^{0}-2e^{-}\to Cu^{+2}} \\ \mathrm{N^{+5}+3e^{-}\to N^{+2}} \end{array} \right|6 \left| \begin{array}{l} \mathrm{3-reducing\;agent} \\ \mathrm{2-oxidizing\;agent} \end{array} \right.$

Answer 2

Balancing the Chemical Equation for the Reaction of Copper with Nitric Acid

To balance the chemical equation for the reaction of copper (Cu) with nitric acid (HNO3) to form copper(II) nitrate (Cu(NO3)2), nitrogen dioxide (NO2), and water (H2O), we need to follow these steps:

1. Write the unbalanced equation: - Cu + HNO3 → Cu(NO3)2 + NO2 + H2O

2. Balance the elements other than hydrogen and oxygen: - The equation is already balanced in terms of copper and nitrogen.

3. Balance the oxygen atoms by adding water molecules: - There are 3 oxygen atoms on the right side (Cu(NO3)2) and 3 oxygen atoms on the left side (HNO3). Therefore, no additional water molecules are needed to balance the oxygen atoms.

4. Balance the hydrogen atoms by adding protons (H+): - There are 3 hydrogen atoms on the left side (HNO3) and 6 hydrogen atoms on the right side (2H2O). To balance the hydrogen atoms, we need to add 3 protons to the left side.

5. Balance the charge by adding electrons: - Since we added 3 protons to the left side, we also need to add 3 electrons to balance the charge.

6. The balanced chemical equation is: - Cu + 4HNO3 → Cu(NO3)2 + 2NO2 + 2H2O

This balanced equation represents the reaction of copper with nitric acid to form copper(II) nitrate, nitrogen dioxide, and water.

I hope this helps you with balancing the chemical equation for the reaction. If you have any further questions or need additional assistance, feel free to ask!