Question

Определите,какое количество вещества сероводорода образуется при взаимодействии сульфида железа (II) с соляной кислотой массой 130 г (массовая доля HCl равна 20%)

Answer 1

Найдем массу HCl в соляной кислоте:
m(HCl) = 130 * 0,2 = 26 г
Найдем количество вещества HCl:
n(HCl) = m(HCl)/M(HCl)= 26/36,5= 0,71 моль
Уравнение реакции:
FeS + 2HCl = FeCl2 + H2S
За уравнением, количество вещества H2S в два раза меньше, чем количество вещества HCl, тогда: 
n(H2S) = 0,71/2 = 0,35 моль

Answer 2

Calculating the Amount of Hydrogen Sulfide Formed

When iron(II) sulfide reacts with hydrochloric acid, hydrogen sulfide gas is produced according to the following chemical equation:

FeS + 2HCl → FeCl2 + H2S

To calculate the amount of hydrogen sulfide formed, we need to consider the stoichiometry of the reaction and the given mass of hydrochloric acid.

The molar ratio of FeS to H2S is 1:1, and the molar ratio of HCl to H2S is 2:1. This means that for every 1 mole of FeS, 1 mole of H2S is produced, and for every 2 moles of HCl, 1 mole of H2S is produced.

Given: - Mass of hydrochloric acid (HCl) = 130 g - Mass fraction of HCl = 20%

First, we need to calculate the moles of HCl: Moles of HCl = (Mass of HCl) / (Molar mass of HCl)

The molar mass of HCl is approximately 36.46 g/mol.

Moles of HCl = 130 g / 36.46 g/mol = 3.56 mol

Since the molar ratio of HCl to H2S is 2:1, we can calculate the moles of H2S produced: Moles of H2S = (Moles of HCl) / 2 = 3.56 mol / 2 = 1.78 mol

Therefore, approximately 1.78 moles of hydrogen sulfide are formed when 130 g of hydrochloric acid with a mass fraction of 20% reacts with iron(II) sulfide.

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