Question

Помогите!1. K-KON-Cu(OH)2-CuSO42.Ba-BaO-Ba(OH)2-BaSO4

Answer 1

1. 1K+2H2O=2KOH+H2
2KOH+CuSO4=-Cu(OH)2+K2SO4
Cu(OH)2 +H2SO4=CuSO4+2H2O
2. 2Ba+O2=2BaO
BaO+H2O-Ba(OH)2
Ba(OH)2+H2SO4=BaSO4+2H2O

Answer 2

Chemical Reactions:

The given chemical reactions are as follows:

1. K-KON-Cu(OH)2-CuSO4 2. Ba-BaO-Ba(OH)2-BaSO4

Let's break down each reaction and discuss them individually.

# Reaction 1: K-KON-Cu(OH)2-CuSO4

The given reaction seems to be incomplete or incorrect. It is not clear what the reactants and products are. Could you please provide more information or clarify the reaction?

# Reaction 2: Ba-BaO-Ba(OH)2-BaSO4

The second reaction involves the transformation of barium (Ba) through different compounds. Here is the breakdown of the reaction:

1. Ba (Barium) reacts with oxygen (O) to form BaO (Barium Oxide). 2. BaO reacts with water (H2O) to form Ba(OH)2 (Barium Hydroxide). 3. Ba(OH)2 can react with sulfuric acid (H2SO4) to form BaSO4 (Barium Sulfate).

Please note that these reactions are simplified representations and may not capture all the details. If you need more information or have specific questions about these reactions, feel free to ask.