Question

Составьте общие и ионные уравнения взаимодействия сульфата железа (III) с хлоридом бария,гидроксидом натрия.СРОЧЧЧЧНННОООО.ПОМОГИТЕ!

Answer 1

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Answer 2

1. Fe₂(SO₄)₃ + 3BaCl₂ = 2FeCl₃ + 3BaSO₄
    2Fe[3+] + 3SO₄[2-] + 3Ba[2+] + 6Cl[-] = 2Fe[3+] + 6Cl[-] + 3BaSO₄
    3Ba[2+] + 3SO₄[2-] = 3BaSO₄

2. Fe₂(SO₄)₃ + 6NaOH = 2Fe(OH)₃ + 3Na₂SO₄
    2Fe[3+] + 3SO₄[2-] + 6Na[+] + 6OH[-] = 2Fe(OH)₃ + 6Na[+] + 3SO₄[2-]
    2Fe[3+] + 6OH[-] = 2Fe(OH)₃

Answer 3

Reaction of Iron(III) sulfate with Barium chloride:

The reaction between Iron(III) sulfate (Fe2(SO4)3) and Barium chloride (BaCl2) can be represented by the following balanced chemical equation:

Fe2(SO4)3 + 3BaCl2 → 2FeCl3 + 3BaSO4

In this reaction, Iron(III) sulfate reacts with Barium chloride to form Iron(III) chloride and Barium sulfate. The Iron(III) sulfate is a compound containing Fe3+ ions and SO4^2- ions, while Barium chloride contains Ba2+ ions and Cl- ions. The reaction results in the exchange of ions between the two compounds, forming Iron(III) chloride and Barium sulfate.

Reaction of Iron(III) sulfate with Sodium hydroxide:

The reaction between Iron(III) sulfate (Fe2(SO4)3) and Sodium hydroxide (NaOH) can be represented by the following balanced chemical equation:

Fe2(SO4)3 + 6NaOH → 2Fe(OH)3 + 3Na2SO4

In this reaction, Iron(III) sulfate reacts with Sodium hydroxide to form Iron(III) hydroxide and Sodium sulfate. The Iron(III) sulfate contains Fe3+ ions and SO4^2- ions, while Sodium hydroxide contains Na+ ions and OH- ions. The reaction results in the exchange of ions between the two compounds, forming Iron(III) hydroxide and Sodium sulfate.

Please note that these equations represent the overall reaction and do not account for the ionic nature of the compounds in solution.