Question

Рассчитайте массу соли, полученной при взаимодействии 2 г магния и раствора, содержащего 2 г HCl

Answer 1

Найдем избыток и решим по недостатку
nMg=m/M=2/24=0.08mol
nHCl=2/36.5=0.05mol в избытке
2g              xg
Mg+2HCl=MgCl2+H2
24g            95g

x=2*95/24=7.9g

Answer 2

Для расчета массы соли, полученной при взаимодействии 2 г магния и раствора, содержащего 2 г HCl, мы можем использовать уравнение реакции между магнием и HCl:

Mg + 2HCl → MgCl2 + H2

Из уравнения видно, что 1 моль магния реагирует с 2 молями HCl, образуя 1 моль MgCl2#### Calculating the Mass of Salt Produced

To calculate the mass of salt produced when 2g of magnesium reacts with a solution containing 2g of HCl, we can use the chemical equation for the reaction between magnesium and hydrochloric acid:

Mg + 2HCl → MgCl2 + H2

The molar mass of magnesium (Mg) is 24.305 g/mol, and the molar mass of hydrochloric acid (HCl) is 36.46 g/mol.

Using the given reaction and molar masses, we can calculate the mass of salt produced.

The balanced chemical equation for the reaction is: Mg + 2HCl → MgCl2 + H2

According to the stoichiometry of the reaction, 1 mole of magnesium reacts with 2 moles of hydrochloric acid to produce 1 mole of magnesium chloride.

Using the molar masses of magnesium and hydrochloric acid, we can calculate the mass of magnesium chloride produced.

The molar mass of magnesium chloride (MgCl2) is 95.211 g/mol.

Using the molar masses and stoichiometry, we can calculate the mass of magnesium chloride produced when 2g of magnesium reacts with 2g of HCl.

The calculation is as follows: - n(Mg) = m/M = 2g / 24.305 g/mol = 0.0822 mol - n(HCl) = m/M = 2g / 36.46 g/mol = 0.0548 mol

From the balanced chemical equation, we know that 1 mole of magnesium reacts with 2 moles of hydrochloric acid to produce 1 mole of magnesium chloride.

Therefore, the limiting reactant is hydrochloric acid, and the amount of magnesium chloride produced will be determined by the amount of hydrochloric acid.

Using the amount of hydrochloric acid, we can calculate the mass of magnesium chloride produced: - n(MgCl2) = n(HCl) = 0.0548 mol - m(MgCl2) = n(MgCl2) * M = 0.0548 mol * 95.211 g/mol = 5.22 g

So, the mass of magnesium chloride produced when 2g of magnesium reacts with a solution containing 2g of HCl is 5.22 grams.

[[SOURCE #8]]