
Вычислите объем газа который образуется при взаимодействии меди 128 г с концентрированой серной
кислотой

Ответы на вопрос

64-----22.4
128-----X
X=44,8



Calculating the Volume of Gas Produced
To calculate the volume of gas produced when copper reacts with concentrated sulfuric acid, we can use the stoichiometry of the reaction to determine the amount of gas produced. The balanced chemical equation for the reaction is:
Cu(s) + 4H2SO4(aq) → CuSO4(aq) + 4H2O(l) + SO2(g)
From the equation, we can see that 1 mole of copper reacts with 4 moles of sulfuric acid to produce 1 mole of sulfur dioxide gas.
Given that the mass of copper is 128 g, we need to convert this mass to moles using the molar mass of copper.
The molar mass of copper (Cu) is approximately 63.55 g/mol.
Using the formula: moles = mass / molar mass
We can calculate the moles of copper involved in the reaction.
Next, we can use the mole ratio from the balanced chemical equation to determine the moles of sulfur dioxide gas produced. Finally, we can convert the moles of gas to volume using the ideal gas law.
Let's calculate the volume of gas produced step by step.
Step 1: Calculate Moles of Copper
The moles of copper can be calculated using the given mass of copper and its molar mass.Moles of copper = 128 g / 63.55 g/mol
Step 2: Use Mole Ratio to Find Moles of Sulfur Dioxide Gas
From the balanced chemical equation, we know that 1 mole of copper produces 1 mole of sulfur dioxide gas.Step 3: Convert Moles of Gas to Volume
Using the ideal gas law, we can convert the moles of gas to volume. The ideal gas law is given by the formula:PV = nRT
Where: P = pressure V = volume n = moles of gas R = ideal gas constant T = temperature
Given that the reaction likely occurs at standard temperature and pressure (STP), we can use the molar volume of an ideal gas at STP, which is approximately 22.414 L/mol.
Conclusion
By following these steps, we can calculate the volume of sulfur dioxide gas produced when 128 g of copper reacts with concentrated sulfuric acid.

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