Question

определите степени окисления атомов хлора в веществах по их формулам : CI2,KCI,CI2O5,KCIO4.

Answer 1

CI2(0),KC(-1)I,CI2O5(+5),KCIO4(+7)

Answer 2

Ci2-0

KCI-(-1)

Ci2O5-+5

KCIO4-+7

Answer 3

Oxidation States of Chlorine Atoms in Compounds

Cl2: The oxidation state of each chlorine atom in Cl2 is 0. This is because in a diatomic molecule, like Cl2, the oxidation state of each atom is 0 .

KCl: In KCl, the oxidation state of chlorine is -1. Potassium (K) has an oxidation state of +1, and since the overall compound is neutral, the oxidation state of chlorine must be -1 .

Cl2O5: In Cl2O5, the oxidation state of each chlorine atom can be calculated as follows: Let the oxidation state of oxygen be -2 (a common rule). The sum of the oxidation states in a compound is equal to the charge of the compound. Since Cl2O5 is neutral, the sum of the oxidation states must be 0. Let the oxidation state of each chlorine atom be x. So, 2x + 5(-2) = 0 2x - 10 = 0 2x = 10 x = 5 Therefore, the oxidation state of each chlorine atom in Cl2O5 is +5 .

KClO4: In KClO4, the oxidation state of chlorine can be calculated as follows: Let the oxidation state of potassium be +1 and oxygen be -2. The sum of the oxidation states in a compound is equal to the charge of the compound. Since KClO4 is neutral, the sum of the oxidation states must be 0. Let the oxidation state of chlorine be x. So, 1 + x + 4(-2) = 0 x - 7 = 0 x = 7 Therefore, the oxidation state of chlorine in KClO4 is +7 .