Question

Осуществить цепь превращений и написать уравнения реакций:PbO->Pb(CH3COO)2->Pb(OH)2->Pb(NO3)2->PbO->PbO2->PbCl2

Answer 1

PbO->Pb(CH3COO)2->Pb(OH)2->Pb(NO3)2->PbO->PbO2->PbCl2
1)PbO+2CH3COOH=(CH3COO)2Pb+H2O

2)(CH3COO)2Pb+2KOH=2CH3COOK+Pb(OH)2

3)Pb(OH)2+2HNO3=Pb(NO3)2+2H2O

4)2Pb(NO3)2=2PbO+4NO2+O2

5)2PbO+O2=2PbO2

6)PbO2+4HCl=Cl2+2H2O+PbCl2

Answer 2

1. PbO -> Pb(CH3COO)2 2PbO + 4CH3COOH -> 2Pb(CH3COO)2 + 2H2O

2. Pb(CH3COO)2 -> Pb(OH)2 Pb(CH3COO)2 + 2NaOH -> Pb(OH)2 + 2CH3COONa

3. Pb(OH)2 -> Pb(NO3)2 Pb(OH)2 + 2HNO3 -> Pb(NO3)2 + 2H2O

4. Pb(NO3)2 -> PbO Pb(NO3)2 -> PbO + 2NO2 + 1/2O2

5. PbO -> PbO2 2PbO -> 2PbO2 + O2

6. PbO2 -> PbCl2 PbO2 + 4HCl -> PbCl2 + 2H2O + Cl2