Question

FE (OH)3 + BN 2+ ..... => K2FEO4 + ..... окислитель и восстановитель + Н2О

Answer 1

 2 Fe(OH)3 + 3 Br2 + 10 KOH = 2 K2FeO4 + 6 KBr + 8 H2O

 

2I Fe(3+) -3e->Fe(6+) востановитель окисление

3I Br2(0) +2e->2Br(-) окислитель востановление

Answer 2

It looks like you've provided a chemical equation. Let's break it down step by step.

Chemical Equation:

The given equation is: Fe(OH)3 + B(OH)3 + 2KOH → K2FeO4 + 2H2O

Balancing the Equation:

First, let's balance the equation. It seems like there might be a typo in the equation you provided, as it's not balanced. I'll assume the correct equation is: Fe(OH)3 + B(OH)3 + 2KOH → 2KFeO4 + 3H2O

Identifying the Oxidizing and Reducing Agents:

In this balanced equation, Fe(OH)3 is being oxidized to FeO4 and B(OH)3 is being reduced to B. The oxidizing agent is the substance that causes another substance to be oxidized, while the reducing agent is the substance that causes another substance to be reduced.

Oxidizing Agent and Reducing Agent:

- The oxidizing agent in this reaction is KOH. - The reducing agent in this reaction is B(OH)3.

Conclusion:

So, in the given chemical equation, KOH acts as the oxidizing agent, and B(OH)3 acts as the reducing agent. This reaction involves the transfer of electrons, where the oxidizing agent gains electrons (is reduced) and the reducing agent loses electrons (is oxidized).