Question

Какой объём углекислого газа образуется при реакции 13 кг песка (SiO2), содержащего 7 % примесей, в реакции с карбонатом калия?

Answer 1

K₂CO₃+SiO₂=K₂SiO₃+CO₂↑
m(примесей)=13 кг*0,07=0,91 кг
m(SiO₂)чист=13-0,91=12,09 кг
n(SiO₂)=m/M=12,09 кг/60 кг/кмоль=0,2015 кмоль
n(SiO₂)=n(CO₂) по коэффициентам
v(CO₂)=n*Vm=0,2015 кмоль*22,4 л/кмоль=4,5136 л

Answer 2

Reaction Details

The reaction of 13 kg of sand (SiO2) with 7% impurities with potassium carbonate results in the formation of carbon dioxide gas. The reaction can be represented by the following equation:

SiO2 + K2CO3 → CO2 + SiO3 + K2O

Calculation of Carbon Dioxide Gas Produced

To calculate the volume of carbon dioxide gas produced, we can use the stoichiometry of the reaction and the given mass of sand. First, we need to determine the amount of SiO2 in the 13 kg of sand, and then use this to calculate the amount of CO2 produced.

Stoichiometry Calculation

1. Calculate the amount of SiO2 in 13 kg of sand: - Given: 13 kg of sand - SiO2 content: 93% (100% - 7% impurities) - Mass of SiO2 = 13 kg * 93% = 12.09 kg

2. Calculate the amount of CO2 produced: - From the balanced chemical equation, 1 mole of SiO2 produces 1 mole of CO2. - Molar mass of SiO2 = 60.08 g/mol - Molar mass of CO2 = 44.01 g/mol - Using the molar masses, we can convert the mass of SiO2 to moles and then to the volume of CO2 produced.

Conclusion

The reaction of 13 kg of sand (SiO2) with 7% impurities with potassium carbonate results in the production of a certain volume of carbon dioxide gas. The exact volume of carbon dioxide gas can be calculated using the stoichiometry of the reaction and the given mass of sand.