Question

Помогите расставить степени окисления и коэффициенты методом электронного баланса в уравнении С6Н12О6+KMnO4+H2SO4 = CO2 + MnSO4 + K2SO4 + H2O. если можно распишите подробно что к чему,буду очень благодарна:)

Answer 1

Коэффициенты получились большие, но кислород сходится, значит по идее правильно.

Answer 2

Balancing the Chemical Equation

To balance the chemical equation for the reaction between C6H12O6, KMnO4, and H2SO4 to produce CO2, MnSO4, K2SO4, and H2O, we need to follow these steps:

1. Identify the Reactants and Products: The reactants are C6H12O6 (fructose), KMnO4 (potassium permanganate), and H2SO4 (sulfuric acid). The products are CO2 (carbon dioxide), MnSO4 (manganese(II) sulfate), K2SO4 (potassium sulfate), and H2O (water).

2. Write the Unbalanced Equation: The unbalanced equation is: C6H12O6 + KMnO4 + H2SO4 = CO2 + MnSO4 + K2SO4 + H2O

3. Balance the Equation: - Balance the elements one at a time, starting with the most complex molecule or polyatomic ion. - Balance the atoms in the following order: C, H, O, Mn, K, and S.

The balanced equation is: `C6H12O6 + 6KMnO4 + 18H2SO4 = 6CO2 + 6MnSO4 + 6K2SO4 + 18H2O`

4. Determine the Oxidation States: - In this reaction, the oxidation states of the elements change. The oxidation state of carbon in C6H12O6 changes from -2 to +4 in CO2, and the oxidation state of manganese in KMnO4 changes from +7 to +2 in MnSO4.

5. Verify the Balancing: - After balancing the equation, ensure that the number of atoms of each element is the same on both sides of the equation.

By following these steps, the chemical equation C6H12O6 + KMnO4 + H2SO4 = CO2 + MnSO4 + K2SO4 + H2O can be balanced using the electron balance method.