Question

Помогите пожалуйста, кому не сложно) Заранее большое спасибо. Осуществите цепочку превращений: CuO-->Cu(NO3)2--->Cu(OH)2--->CuCl2-->CuCl

Answer 1

CuO+2HNO3==Cu(NO3)2+H2O
Cu(NO3)2+2NaOH==Cu(OH)2+2NaNO3
Cu(OH)2+HCl==CuCl2+2 H2O
CuCl2+HOH==Cu(OH)Cl+HCl
CuCl получить невозможно

Answer 2

Chain of Transformations: CuO -> Cu(NO3)2 -> Cu(OH)2 -> CuCl2 -> CuCl

To understand the chain of transformations from CuO to CuCl, let's break it down step by step:

1. CuO to Cu(NO3)2: - CuO is copper(II) oxide, and Cu(NO3)2 is copper(II) nitrate. - To convert CuO to Cu(NO3)2, we need to react CuO with nitric acid (HNO3). - The balanced chemical equation for this reaction is: ``` CuO + 2HNO3 -> Cu(NO3)2 + H2O ```

2. Cu(NO3)2 to Cu(OH)2: - Cu(NO3)2 is copper(II) nitrate, and Cu(OH)2 is copper(II) hydroxide. - To convert Cu(NO3)2 to Cu(OH)2, we need to react Cu(NO3)2 with sodium hydroxide (NaOH). - The balanced chemical equation for this reaction is: ``` Cu(NO3)2 + 2NaOH -> Cu(OH)2 + 2NaNO3 ```

3. Cu(OH)2 to CuCl2: - Cu(OH)2 is copper(II) hydroxide, and CuCl2 is copper(II) chloride. - To convert Cu(OH)2 to CuCl2, we need to react Cu(OH)2 with hydrochloric acid (HCl). - The balanced chemical equation for this reaction is: ``` Cu(OH)2 + 2HCl -> CuCl2 + 2H2O ```

4. CuCl2 to CuCl: - CuCl2 is copper(II) chloride, and CuCl is copper(I) chloride. - To convert CuCl2 to CuCl, we need to reduce the copper(II) ion to copper(I) ion. - This can be achieved by adding a reducing agent, such as ascorbic acid (vitamin C). - The balanced chemical equation for this reduction reaction is: ``` CuCl2 + 2HCl + 2H2O + 2C6H8O6 -> 2CuCl + 2CO2 + 8H2O ```

So, the complete chain of transformations from CuO to CuCl is as follows: CuO -> Cu(NO3)2 -> Cu(OH)2 -> CuCl2 -> CuCl.

Please note that the reactions mentioned above are simplified and may not represent the actual conditions or procedures used in a laboratory setting. It is always important to consult reliable sources and perform experiments under appropriate guidance when conducting chemical reactions.

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