
Расставьте коэффициенты методом электронного баланса. Cr+HNO3->Cr(NO3)3+H2O+N2O


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Balancing the Chemical Equation: Cr + HNO3 -> Cr(NO3)3 + H2O + N2O
To balance the chemical equation: Cr + HNO3 -> Cr(NO3)3 + H2O + N2O, we can use the method of electronic balancing. This method involves balancing the atoms and charges on both sides of the equation.
Let's go step by step:
Step 1: Count the number of atoms for each element on both sides of the equation.
On the left side (reactants): - Cr: 1 atom - H: 1 atom - N: 1 atom - O: 3 atoms
On the right side (products): - Cr: 1 atom - H: 2 atoms - N: 3 atoms - O: 11 atoms
Step 2: Balance the atoms of each element.
To balance the atoms of each element, we need to adjust the coefficients in front of the reactants and products. Let's start with the elements that appear in the fewest compounds.
1. Balance the nitrogen (N) atoms: - There is 1 N atom on the left side and 3 N atoms on the right side. - To balance the N atoms, we need to put a coefficient of 3 in front of HNO3 on the left side.
The equation becomes: Cr + 3HNO3 -> Cr(NO3)3 + H2O + N2O
2. Balance the hydrogen (H) atoms: - There is 1 H atom on the left side and 2 H atoms on the right side. - To balance the H atoms, we need to put a coefficient of 2 in front of H2O on the right side.
The equation becomes: Cr + 3HNO3 -> Cr(NO3)3 + 2H2O + N2O
3. Balance the oxygen (O) atoms: - There are 3 O atoms on the left side and 11 O atoms on the right side. - To balance the O atoms, we need to put a coefficient of 8 in front of HNO3 on the left side.
The equation becomes: Cr + 8HNO3 -> Cr(NO3)3 + 2H2O + N2O
4. Balance the chromium (Cr) atoms: - There is 1 Cr atom on both sides, so it is already balanced.
The final balanced equation is: Cr + 8HNO3 -> Cr(NO3)3 + 2H2O + N2O.
Please note that the balanced equation may not be the only possible solution, but it satisfies the requirement of balancing the atoms and charges on both sides of the equation.


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