Question

Какой объем водорода (н.у.) выделится, если в реакцию с соляной кислотой вступит 26 г. цинка?

Answer 1

Дано:
m(Zn)=26г
с HCl
V(H2)-?

Zn+2HCl=ZnCl2+H2
M(Zn)=65г
26:65=х:22.4
х=(26*22.4):65=8.96л

Answer 2

Calculating the volume of hydrogen gas produced

The reaction of zinc with hydrochloric acid produces hydrogen gas as one of its products. The balanced chemical equation for this reaction is:

`Zn(s) + 2HCl(aq) → ZnCl2(aq) + H2(g)`

To calculate the volume of hydrogen gas produced, we first need to determine the number of moles of zinc that will react. Given that 26 g of zinc is used:

- Zinc has a molar mass of 65 g/mol - Using the formula: Moles = Mass / Molar Mass - Moles of zinc = 26 g / 65 g/mol = 0.4 moles

According to the balanced equation, every 1 mole of zinc reacts with 2 moles of HCl to produce 1 mole of H2 gas.

Therefore, the number of moles of hydrogen gas produced is equal to the number of moles of zinc reacted:

- Moles of H2 = 0.4 moles

Finally, to calculate the volume of hydrogen gas at standard temperature and pressure (STP):

- 1 mole of any gas occupies 22.4 L at STP - Volume of H2 = Moles of H2 x Volume per mole = 0.4 moles x 22.4 L/mole = 9 L

So the volume of hydrogen gas produced from the reaction of 26 g of zinc with hydrochloric acid is 9 L.