Question

Какая масса этанола получится при взаимодействии 32,7 грамм бромэтана с водой,если массовая доля равна 85%

Answer 1

Данная реакция протекает по уравнению: C2H5Br+H2O=C2H5OH+HBr. Сначала находим массу бромэтана, так как его массовая доля 85%, то 32,7*0,85=27,795г. Теперь Находим молярные массы бромэтана и этанола. У бромэтана молярная масса составит: 12*2+1*5+80*1=109 г. У этанола: 12*2+1*5+1*16+1*1= 46 г. Теперь сотавлем уравнение: 27,795:109=х:46. Отсюда х = 11,73 г. То есть масса этанола составит 11,73 г.

Answer 2

Calculating the Mass of Ethanol Produced from the Reaction

To calculate the mass of ethanol produced from the reaction of 32.7 grams of bromoethane with water, we can use the given mass fraction of 85% and the chemical equation for the reaction.

The balanced chemical equation for the reaction of bromoethane (C2H5Br) with water (H2O) to produce ethanol (C2H5OH) and hydrogen bromide (HBr) is:

C2H5Br + H2O → C2H5OH + HBr

From the balanced chemical equation, we can see that 1 mole of bromoethane reacts with 1 mole of water to produce 1 mole of ethanol. Now, let's calculate the mass of ethanol produced.

Calculation Steps

1. Calculate the moles of bromoethane (C2H5Br) using its molar mass. 2. Use the mole ratio from the balanced chemical equation to find the moles of ethanol produced. 3. Convert the moles of ethanol to grams using its molar mass.

Step 1: Calculate the Moles of Bromoethane

The molar mass of bromoethane (C2H5Br) is approximately 108.97 g/mol.

Moles of C2H5Br = Mass of C2H5Br / Molar mass of C2H5Br Moles of C2H5Br = 32.7 g / 108.97 g/mol Moles of C2H5Br ≈ 0.300 moles

Step 2: Use the Mole Ratio

From the balanced chemical equation, the mole ratio of C2H5Br to C2H5OH is 1:1.

So, moles of C2H5OH produced = Moles of C2H5Br reacted = 0.300 moles

Step 3: Convert Moles to Grams

The molar mass of ethanol (C2H5OH) is approximately 46.07 g/mol.

Mass of C2H5OH = Moles of C2H5OH * Molar mass of C2H5OH Mass of C2H5OH = 0.300 moles * 46.07 g/mol Mass of C2H5OH ≈ 13.82 grams

Therefore, the mass of ethanol produced from the reaction of 32.7 grams of bromoethane with water, with a mass fraction of 85%, is approximately 13.82 grams.