Question

Используя формулу M = m/v [г/моль], рассчитайте(запишите ответ)Какое количество вещества содержится вобразце карбоната натрия Na2CO3 массой 10г?

Answer 1

Дано:                                                   Решение:

m(Na2CO3) = 10 г                       v(Na2CO3) = m/М = 10 / 106 = 0,09 моль

М(Na2CO3) = 106г/моль

Найти:

n(Na2CO3) =?

Answer 2

Calculating the Amount of Substance in Sodium Carbonate (Na2CO3)

To calculate the amount of substance (in moles) contained in a sample of sodium carbonate (Na2CO3) with a mass of 10g, we can use the formula:

Moles (n) = mass (m) / molar mass (M)

Where: - m = mass of the substance - M = molar mass of the substance

Molar Mass of Sodium Carbonate (Na2CO3)

The molar mass of sodium carbonate (Na2CO3) can be calculated by adding the atomic masses of its constituent elements.

- Atomic mass of Na = 22.99 g/mol - Atomic mass of C = 12.01 g/mol - Atomic mass of O = 16.00 g/mol

Using the formula: Molar mass (M) = 2 * (atomic mass of Na) + atomic mass of C + 3 * (atomic mass of O)

Substituting the values: M = 2 * 22.99 g/mol + 12.01 g/mol + 3 * 16.00 g/mol

Calculating the molar mass: M = 2 * 22.99 g/mol + 12.01 g/mol + 48.00 g/mol M = 45.98 g/mol + 12.01 g/mol + 48.00 g/mol M = 105.99 g/mol

Calculating the Amount of Substance

Now, we can use the molar mass (M) and the given mass (m) to calculate the amount of substance (n) in moles.

Substituting the values: n = 10g / 105.99 g/mol

Calculating the amount of substance: n ≈ 0.094 moles

Therefore, the amount of substance contained in a sample of sodium carbonate (Na2CO3) with a mass of 10g is approximately 0.094 moles.