Question

Сколько граммов гидроксида калия необходимое для нейтрализации 400 г раствора серной кислоты с массовой долей кислоты 8%

Answer 1

Ответ : приблизительно 36,6 грамм

Answer 2

Calculating the Amount of Potassium Hydroxide Needed to Neutralize Sulfuric Acid Solution

To calculate the amount of potassium hydroxide (KOH) needed to neutralize 400g of a sulfuric acid (H2SO4) solution with a mass fraction of 8%, we can use the following chemical equation:

H2SO4 + 2KOH → K2SO4 + 2H2O

According to the balanced chemical equation, 1 mole of sulfuric acid reacts with 2 moles of potassium hydroxide. From this, we can calculate the molar mass of sulfuric acid and potassium hydroxide to determine the amount needed.

Calculation Steps:

1. Calculate the molar mass of sulfuric acid (H2SO4). 2. Determine the number of moles of sulfuric acid in the given solution. 3. Use the mole ratio from the balanced chemical equation to find the moles of potassium hydroxide needed. 4. Convert the moles of potassium hydroxide to grams.

Step 1: Calculate the Molar Mass of Sulfuric Acid (H2SO4)

The molar mass of sulfuric acid (H2SO4) can be calculated as follows: - Hydrogen (H): 1.01 g/mol - Sulfur (S): 32.07 g/mol - Oxygen (O): 16.00 g/mol

Molar mass of H2SO4 = 2(1.01) + 32.07 + 4(16.00) = 98.09 g/mol

Step 2: Determine the Number of Moles of Sulfuric Acid in the Solution

Given mass fraction of sulfuric acid = 8% Mass of sulfuric acid in the solution = 8% of 400g = 0.08 * 400g = 32g

Number of moles of sulfuric acid = Mass / Molar mass = 32g / 98.09 g/mol

Step 3: Use the Mole Ratio to Find the Moles of Potassium Hydroxide Needed

From the balanced chemical equation, 1 mole of sulfuric acid reacts with 2 moles of potassium hydroxide.

Step 4: Convert the Moles of Potassium Hydroxide to Grams

Once the moles of potassium hydroxide are determined, they can be converted to grams using the molar mass of potassium hydroxide.

I will now calculate the moles of potassium hydroxide needed and convert them to grams.