Question

В какой массе NA2SO4 содержится 54 г атомов кислорода?

Answer 1

М(Na2SO4) = 46 + 32 + 64 = 142 г/моль.

М(О4) = 64 г/моль.

Тогда пропоция для х - массы Na2SO4:

142   -   64

  х    -    54

 х = 142*54/64 = 120 г

Ответ: 120 г.

Answer 2

Calculating the Mass of Na2SO4 Containing 54g of Oxygen Atoms

To calculate the mass of Na2SO4 containing 54g of oxygen atoms, we can use the molar mass of Na2SO4 and the molar mass of oxygen to find the mass of Na2SO4.

Step 1: Calculate the Molar Mass of Na2SO4 The molar mass of Na2SO4 can be calculated by adding the atomic masses of its constituent elements.

The molar mass of Na2SO4 is: 2(Na) + 1(S) + 4(O) = 2(22.99) + 32.07 + 4(16.00) = 45.98 + 32.07 + 64.00 = 142.05 g/mol

Step 2: Calculate the Mass of Na2SO4 Containing 54g of Oxygen Atoms To find the mass of Na2SO4 containing 54g of oxygen atoms, we can use the following formula: \[ \text{Mass of Na2SO4} = \frac{54g}{\text{Molar mass of oxygen}} \times \text{Molar mass of Na2SO4} \]

Using the molar mass of oxygen: Molar mass of oxygen = 16.00 g/mol

\[ \text{Mass of Na2SO4} = \frac{54g}{16.00g/mol} \times 142.05g/mol \] \[ \text{Mass of Na2SO4} = 3.375 \times 142.05g \] \[ \text{Mass of Na2SO4} = 479.44g \]

Answer: The mass of Na2SO4 containing 54g of oxygen atoms is approximately 479.44 grams.