Question

атомна маса елемента А в 1,4375 рази більша за атомну масу елемента В. Сума атомних мас елементів А і В дорівнює 39. Знайти невідомі елементи А і В.

Answer 1

пусть x - атомная масса элемента А

тогда 1,4375x - атомная масса элемента B

A + B = 39

x + 1,4375x=39

2,4375x=39

x=16 г/моль - по таблице Менделеева это кислород (O₂) - элемент А

1,4375*16 г/моль = 23 г/моль - по таблице Менделеева это натрий (Na) - элемент B

Ответ: A - O₂, B - Na.

Answer 2

Atomic Mass of Element A and Element B

The atomic mass of element A is 1.4375 times greater than the atomic mass of element B. The sum of the atomic masses of elements A and B is equal to 39. We need to find the unknown elements A and B.

To solve this problem, we can set up a system of equations based on the given information.

Let's assume the atomic mass of element B is x. Therefore, the atomic mass of element A would be 1.4375x.

The sum of the atomic masses of elements A and B is equal to 39, so we can write the equation:

x + 1.4375x = 39

Simplifying the equation:

2.4375x = 39

Dividing both sides of the equation by 2.4375:

x = 39 / 2.4375

Calculating the value of x:

x ≈ 15.99

Now that we have the value of x, we can find the atomic mass of element A:

Atomic mass of element A = 1.4375 * 15.99 ≈ 22.98

Therefore, the unknown elements A and B have atomic masses of approximately 22.98 and 15.99, respectively.

Please note that the values provided are approximate due to rounding.