Question

какой объем ацетилена можно получить при взаимодействии 51,2кг карбида кальция с водой , если массовая доля выхода ацетилена составляет 0,84 от теоретического выхода продукта?

Answer 1

СаС2 + 2Н2О → Са(ОН)2 + С2Н2 
51200гр./64гр/моль=800моль карбида,значит ацетилена тоже 800 моль. 
один моль газа при н.у занимает 22.4 литра. 
V(ацетилена)800*22,4=17 920 литра(теоретически) 
практически 17 920л.*0,84=15 052,8 литра

Answer 2

Calculating the Volume of Acetylene Produced

To calculate the volume of acetylene produced when 51.2 kg of calcium carbide reacts with water, we can use the mass of calcium carbide and the mass fraction of the theoretical yield of acetylene.

Given: - Mass of calcium carbide (CaC2) = 51.2 kg - Mass fraction of the theoretical yield of acetylene = 0.84

Calculation Steps

1. Molar Mass of Calcium Carbide (CaC2): - The molar mass of CaC2 is 64.1 g/mol.

2. Moles of Calcium Carbide: - Moles = Mass / Molar Mass - Moles of CaC2 = 51,200 g / 64.1 g/mol

3. Moles of Acetylene Produced: - The balanced chemical equation for the reaction is: CaC2 + 2H2O → Ca(OH)2 + C2H2 - From the equation, 1 mole of CaC2 produces 1 mole of C2H2.

4. Mass of Acetylene Produced: - Mass of C2H2 = Mass of CaC2 * Mass fraction of acetylene - Mass of C2H2 = 51.2 kg * 0.84

5. Moles of Acetylene Produced: - Moles of C2H2 = Mass of C2H2 / Molar Mass of C2H2 - Molar Mass of C2H2 is 26.04 g/mol.

6. Volume of Acetylene Produced: - Volume = Moles * Molar Volume at STP (Standard Temperature and Pressure)

Conclusion

The volume of acetylene produced can be calculated using the above steps.