Question

Скільки мілілітрів розчину сірчаної кислоти (p=1,260г/см3 (в квадраті) при 20 градусах)піде на повну нейтралізацію гідроксиду натрію масою 80 г?Пожалуста срочно нужно прошу!!!!

Answer 1

Дано:
ρ(H₂SO₄) = 1.260 г/см³
m(NaOH) = 80 г
Знайти:
V(H₂SO₄) - ?
M(NaOH) = 40 г/моль
n(NaOH) = m(NaOH)/M(NaOH) = 80 г/40 г/моль = 2 моль
H₂SO₄ + 2NaOH = Na₂SO₄ + 2H₂O
M(H₂SO₄) = 98 г/моль
З рівняння реакції слідує, що n(H₂SO₄) = ¹/₂n(NaOH) = 1 моль
m(H₂SO₄) = n(H₂SO₄)*M(H₂SO₄) = 1 моль*98 г/моль = 98 г
V(H₂SO₄) = m(H₂SO₄)/ρ(H₂SO₄) = 98 г/1,260 г/см³ = 77,78 см³
Відповідь: 77,78 см³

Answer 2

Calculation of Sulfuric Acid Solution Needed for Neutralization

To calculate the amount of sulfuric acid solution needed to fully neutralize 80g of sodium hydroxide, we can use the following chemical equation:

H2SO4 + 2NaOH → Na2SO4 + 2H2O

The molar mass of sulfuric acid (H2SO4) is 98.08 g/mol, and the molar mass of sodium hydroxide (NaOH) is 40.00 g/mol.

First, we need to find the number of moles of sodium hydroxide:

Number of moles = Mass / Molar mass Number of moles = 80g / 40.00 g/mol Number of moles = 2 moles

According to the balanced chemical equation, 1 mole of sulfuric acid reacts with 2 moles of sodium hydroxide. Therefore, the number of moles of sulfuric acid needed is half the number of moles of sodium hydroxide:

Number of moles of H2SO4 = 2 moles / 2 Number of moles of H2SO4 = 1 mole

Now, we can calculate the volume of sulfuric acid solution needed using the density and molar mass of sulfuric acid:

Volume = (Number of moles * Molar mass) / Density Volume = (1 mole * 98.08 g/mol) / 1.260 g/cm³ Volume ≈ 77.78 cm³

Therefore, approximately 77.78 milliliters of sulfuric acid solution at a density of 1.260 g/cm³ would be needed to fully neutralize 80g of sodium hydroxide at 20 degrees Celsius.