Question

У результаті взаємодії цинку з хлоридною кислотою утвориться цинк хлорид та водень обчисліть масу цинку якщо виділився водень об'ємом 4,48 л

Answer 1

Дано:
V(H2)=4.48 л
Найти:
m(Zn)=?

Решение:
M(Zn)=65 г/моль, Vm=22.4 л/моль
х г                      4.48 л
Zn+2HCl=ZnCl2+H2
65                       22.4
m(Zn)= х г
x/65=4.48/22.4
x=13
Ответ: масса цинка 13 г.

Answer 2

Chemical Reaction and Calculation of Zinc Mass

When zinc reacts with hydrochloric acid, it forms zinc chloride and hydrogen gas. The balanced chemical equation for this reaction is:

Zn + 2HCl → ZnCl2 + H2

To calculate the mass of zinc produced when 4.48 L of hydrogen gas is released, we can use the molar volume of a gas at standard temperature and pressure (STP), which is 22.4 L/mol.

First, we need to determine the number of moles of hydrogen gas produced using the ideal gas law:

PV = nRT

Where: - P = pressure (at STP, this is 1 atm) - V = volume of gas (4.48 L) - n = number of moles - R = ideal gas constant (0.0821 L.atm/mol.K) - T = temperature (at STP, this is 273 K)

Using the ideal gas law, we can solve for the number of moles of hydrogen gas produced.

Next, we can use the stoichiometry of the balanced chemical equation to relate the moles of hydrogen gas to the moles of zinc. From the balanced equation, we know that 1 mole of zinc reacts with 2 moles of hydrochloric acid to produce 1 mole of hydrogen gas. Therefore, the moles of hydrogen gas produced will be equal to the moles of zinc consumed.

Finally, we can use the molar mass of zinc (65.38 g/mol) to convert moles of zinc to grams, and then to find the mass of zinc.

Let's calculate the mass of zinc using the given volume of hydrogen gas.