Question

во сколько раз изменится скорость прямой реакции 2so2+o2=2so3 если увеличить давление в 3 раза?желательно решить с объяснением...

Answer 1

При увеличении в 3 раза давления. увеличивается концентрация исходных веществ во столько же раз. Поэтому скорость реакции = k·32·3=27k, т.е. скорость увеличится в 27 раз.

 

 

Answer 2

Calculating the Change in Reaction Rate with Increased Pressure

To calculate the change in the speed of the direct reaction 2SO2 + O2 = 2SO3 when the pressure is increased by a factor of 3, we can use the concept of reaction rate and the effect of pressure on the reaction.

The rate of a chemical reaction is affected by the concentration of the reactants and the temperature. According to the collision theory, an increase in pressure will result in an increase in the frequency of collisions between the reactant molecules, leading to an increase in the reaction rate.

When the pressure is increased, the reaction will adjust to relieve the stress caused by the change in pressure. For a reaction involving gases, the reaction will shift in the direction that reduces the total number of gas molecules.

Explanation and Calculation

In the given reaction 2SO2 + O2 = 2SO3, the total number of gas molecules on the left side of the equation is 3 (2 moles of SO2 and 1 mole of O2), and on the right side, it is also 3 (2 moles of SO3).

When the pressure is increased, the reaction will shift to the side with fewer gas molecules to relieve the stress caused by the change in pressure. In this case, since the total number of gas molecules is the same on both sides of the equation, the change in pressure will not affect the equilibrium position of the reaction.

Therefore, the speed of the direct reaction 2SO2 + O2 = 2SO3 will not change when the pressure is increased by a factor of 3.

Conclusion

The speed of the direct reaction 2SO2 + O2 = 2SO3 will not change when the pressure is increased by a factor of 3.