Question

Сера -->Сернистый Газ-->Сульфит Натрия.Расчитать Массу Соли полученной Из Технической Серы .3,10 Грамма, Содержащий 25% Примиси. Химия 9 Класс

Answer 1

S + O2 = SO2 

 

m(S)= (3,10 * 75%) / 100% = 2,325

m(SO2) = (2,325*64)/32 = 4,65

 

 

2NaOH + SO2 = Na2SO3 + H2O

 

m(Na2SO3) = (4,65*126)/ 64 = 9,15 

вроде бы так...)

Answer 2

Calculating the Mass of Sodium Sulfite Obtained from Technical Sulfur

To calculate the mass of sodium sulfite obtained from technical sulfur, we can use the given information about the mass of technical sulfur and its impurity percentage.

Given: - Mass of technical sulfur = 3.10 grams - Impurity percentage = 25%

Calculations

1. Calculate the mass of pure sulfur: - Mass of impure sulfur = 3.10 grams - Impurity percentage = 25% - Mass of impurities = 3.10 grams * 25% = 0.775 grams - Mass of pure sulfur = Mass of impure sulfur - Mass of impurities = 3.10 grams - 0.775 grams = 2.325 grams

2. Calculate the molar mass of sulfur (S): - The molar mass of sulfur (S) = 32.07 g/mol

3. Calculate the number of moles of sulfur: - Number of moles of sulfur = Mass of pure sulfur / Molar mass of sulfur = 2.325 grams / 32.07 g/mol

4. Use stoichiometry to find the mass of sodium sulfite: - The balanced chemical equation for the reaction is: - S (sulfur) + 2 NaOH (sodium hydroxide) + H2O (water) → Na2SO3 (sodium sulfite) + 2 H2O (water) - From the balanced equation, we can see that 1 mole of sulfur reacts to form 1 mole of sodium sulfite (Na2SO3).

5. Calculate the mass of sodium sulfite: - Mass of sodium sulfite = Number of moles of sulfur * Molar mass of sodium sulfite

Conclusion

The calculated mass of sodium sulfite obtained from 3.10 grams of technical sulfur containing 25% impurity is the result of the above calculations.