Question

СРОЧНО!!!!!!для повного розкладання 25 грамм карбоната кальция затрачено 39,5 килоджоули теплоты.складіть термохімічне ріаняння цієї реакції

Answer 1

Складаємо рівняння:
25г                           39,5кДж
СаСО3=СаО+СО2+Q
100г                          х

пропорція:
25-----------39,5
100--------х
х=100*39,5/25=158 
відповідь   СаСО3=СаО+СО2+158 кДж

Answer 2

Thermochemical Equation for the Decomposition of Calcium Carbonate

To calculate the thermochemical equation for the decomposition of calcium carbonate, we can use the given information that 25 grams of calcium carbonate releases 39.5 kilojoules of heat.

Step 1: Calculate the Molar Mass of Calcium Carbonate

The molar mass of calcium carbonate (CaCO3) can be calculated by adding the atomic masses of calcium (Ca), carbon (C), and three oxygen atoms (O).

The atomic masses are: - Ca: 40.08 g/mol - C: 12.01 g/mol - O: 16.00 g/mol

So, the molar mass of CaCO3 is: ``` Molar mass of CaCO3 = 40.08 + 12.01 + (3 * 16.00) = 100.09 g/mol ```

Step 2: Calculate the Number of Moles of Calcium Carbonate

Using the given mass of calcium carbonate (25 grams) and its molar mass, we can calculate the number of moles: ``` Number of moles = Mass / Molar mass = 25 g / 100.09 g/mol = 0.2499 mol ```

Step 3: Calculate the Heat Released per Mole of Calcium Carbonate

To find the heat released per mole of calcium carbonate, we divide the given heat by the number of moles: ``` Heat released per mole = 39.5 kJ / 0.2499 mol = 158.1 kJ/mol ```

Step 4: Write the Thermochemical Equation

The thermochemical equation for the decomposition of calcium carbonate can be written as follows, based on the information obtained: ``` CaCO3(s) → CaO(s) + CO2(g) ΔH = -158.1 kJ/mol ```

This equation represents the decomposition of calcium carbonate into calcium oxide and carbon dioxide, with the release of 158.1 kilojoules of heat per mole of calcium carbonate.