Question

Рассчитать массу FePo4

Answer 1

Молекулярная масса of FePO4 is 150,8164 g/mol

Answer 2

Молочная масса of FePo4is 891,7747g/mol

Answer 3

Calculation of the Mass of FePO4

To calculate the mass of FePO4 (iron(III) phosphate), we need to know the molar mass of each element in the compound and then sum them up.

The molar mass of iron (Fe) is approximately 55.845 g/mol, phosphorus (P) is approximately 30.974 g/mol, and oxygen (O) is approximately 15.999 g/mol.

The formula for FePO4 indicates that there is one iron atom, one phosphorus atom, and four oxygen atoms in each molecule of FePO4.

Using this information, we can calculate the molar mass of FePO4 as follows:

Molar mass of FePO4 = (1 * molar mass of Fe) + (1 * molar mass of P) + (4 * molar mass of O)

Molar mass of FePO4 = (1 * 55.845 g/mol) + (1 * 30.974 g/mol) + (4 * 15.999 g/mol)

Molar mass of FePO4 = 55.845 g/mol + 30.974 g/mol + 63.996 g/mol

Molar mass of FePO4 = 150.815 g/mol

Therefore, the molar mass of FePO4 is approximately 150.815 g/mol.