Question

написать молекулярное полное ионное сокращенное ионное уравнение взаимодействия гидроксида железа(2) и серной кислоты

Answer 1

Fe(OH)2+H2SO4=FeSO4+2H2O

Fe(OH)2+2H(+) +SO4(2-) =Fe(2+) +SO4(2-) +2H2O

Fe(OH)2+2H(+) =Fe(2+)+2H2O

Answer 2

Molecular Equation:

The molecular equation for the interaction between iron(II) hydroxide and sulfuric acid is:

Fe(OH)2 + H2SO4 → FeSO4 + 2H2O

Ionic Equation:

The ionic equation for the interaction between iron(II) hydroxide and sulfuric acid is:

Fe(OH)2 + H2SO4 → FeSO4 + 2H2O

Fe^2+ + 2OH^- + H2SO4 → FeSO4 + 2H2O

In the ionic equation, the hydroxide ion (OH^-) from iron(II) hydroxide reacts with the hydrogen ion (H^+) from sulfuric acid to form water (H2O). The iron(II) ion (Fe^2+) combines with the sulfate ion (SO4^2-) to form iron(II) sulfate (FeSO4).

Net Ionic Equation:

The net ionic equation for the interaction between iron(II) hydroxide and sulfuric acid is:

Fe(OH)2 + H2SO4 → FeSO4 + 2H2O

Fe^2+ + 2OH^- + H^+ → FeSO4 + 2H2O

In the net ionic equation, the hydroxide ion (OH^-) and the hydrogen ion (H^+) combine to form water (H2O). The iron(II) ion (Fe^2+) reacts with the sulfate ion (SO4^2-) to form iron(II) sulfate (FeSO4).

Please note that the above equations are based on the information provided in the search results.