Question

Какую реакцию среды должны показывать водные растворы нитрата бария, нитрата аммония, сульфита калия, сульфата алюминия? Записать уравнение гидролиза. .Яку реакцію середовища повинні показувати водні розчини нітрату барію, нітрату амонію, сульфіту калію, сульфату алюмінію? Записати рівняння гідролізу. ПОМОГИТЕ ОЧЕНЬ НАДО

Answer 1

Реакція середовища повинна бути активною, тому що всі ці солі призводять до вироблення активних кислот та баз.

Рівняння гідролізу:

2HNO3 + 2KNO3 + Na2SO4 + Al2(SO4)3 → 4H2O + 2KNO2 + 2NaNO3 + 2Al(OH)3

Answer 2

Hydrolysis of Aqueous Solutions of Barium Nitrate, Ammonium Nitrate, Potassium Sulfite, and Aluminum Sulfate

When dissolved in water, certain salts can undergo hydrolysis, which is a chemical reaction between the salt and water molecules. This reaction can result in the formation of acidic or basic species, depending on the nature of the salt. Let's examine the hydrolysis reactions of aqueous solutions of barium nitrate, ammonium nitrate, potassium sulfite, and aluminum sulfate.

Hydrolysis of Barium Nitrate (Ba(NO3)2)

Barium nitrate (Ba(NO3)2) is a salt that dissociates into barium ions (Ba2+) and nitrate ions (NO3-) when dissolved in water. The hydrolysis of barium nitrate can be represented by the following equation:

Ba(NO3)2 + 2H2O → Ba(OH)2 + 2HNO3

In this reaction, water molecules (H2O) react with the barium ions (Ba2+) to form barium hydroxide (Ba(OH)2) and nitric acid (HNO3). Barium hydroxide is a strong base, while nitric acid is a strong acid.

Hydrolysis of Ammonium Nitrate (NH4NO3)

Ammonium nitrate (NH4NO3) is a salt that dissociates into ammonium ions (NH4+) and nitrate ions (NO3-) when dissolved in water. The hydrolysis of ammonium nitrate can be represented by the following equation:

NH4NO3 + H2O → NH4OH + HNO3

In this reaction, water molecules (H2O) react with the ammonium ions (NH4+) to form ammonium hydroxide (NH4OH) and nitric acid (HNO3). Ammonium hydroxide is a weak base, while nitric acid is a strong acid.

Hydrolysis of Potassium Sulfite (K2SO3)

Potassium sulfite (K2SO3) is a salt that dissociates into potassium ions (K+) and sulfite ions (SO3^2-) when dissolved in water. The hydrolysis of potassium sulfite can be represented by the following equation:

K2SO3 + H2O → 2KOH + H2SO3

In this reaction, water molecules (H2O) react with the potassium ions (K+) to form potassium hydroxide (KOH) and sulfurous acid (H2SO3). Potassium hydroxide is a strong base, while sulfurous acid is a weak acid.

Hydrolysis of Aluminum Sulfate (Al2(SO4)3)

Aluminum sulfate (Al2(SO4)3) is a salt that dissociates into aluminum ions (Al3+) and sulfate ions (SO4^2-) when dissolved in water. The hydrolysis of aluminum sulfate can be represented by the following equation:

Al2(SO4)3 + 6H2O → 2Al(OH)3 + 3H2SO4

In this reaction, water molecules (H2O) react with the aluminum ions (Al3+) to form aluminum hydroxide (Al(OH)3) and sulfuric acid (H2SO4). Aluminum hydroxide is a weak base, while sulfuric acid is a strong acid.

It is important to note that the extent of hydrolysis and the resulting pH of the solution depend on the strength of the acid or base formed during the reaction. Strong acids and bases completely dissociate in water, while weak acids and bases only partially dissociate. The pH of the resulting solution can be determined by considering the strength of the acid or base formed and the concentration of the salt in the solution.

I hope this helps! Let me know if you have any further questions.