Question

Найти массу вступившей в реакцию соли( нитрата меди (II)) с гидроксидом натрия, если образуется 300г 20%-ного раствора нитрата натрия.

Answer 1

Cu(NO3)2+2NaOH=2NaNO3+Cu(OH)2
m(NaNO3)=300*0,2=60 г
∨(NaNO3)=60/85=0,7 моль
m(Cu(NO3)2)=0,7/2*188=132,7 г

Answer 2

Finding the Mass of Reacted Copper(II) Nitrate with Sodium Hydroxide

To find the mass of the reacted copper(II) nitrate with sodium hydroxide, we can use the information provided in the search results.

Given: - 300g of 20%-concentration sodium nitrate solution is formed.

Steps: 1. Calculate the amount of sodium nitrate in the solution. 2. Use the stoichiometry of the reaction between copper(II) nitrate and sodium hydroxide to find the mass of copper(II) nitrate.

Step 1: Calculate the Amount of Sodium Nitrate in the Solution

The given information is that 300g of 20%-concentration sodium nitrate solution is formed. We can calculate the amount of sodium nitrate in the solution using the concentration and the total mass of the solution.

The formula for the concentration of a solution is: Concentration = (Mass of solute / Total mass of solution) * 100

Using this formula, we can calculate the mass of sodium nitrate in the solution.

Step 2: Use Stoichiometry to Find the Mass of Copper(II) Nitrate

The reaction between copper(II) nitrate and sodium hydroxide can be represented as: Cu(NO3)2 + 2NaOH → Cu(OH)2 + 2NaNO3

From the balanced chemical equation, we can see that 1 mole of copper(II) nitrate reacts with 2 moles of sodium hydroxide.

We can use the amount of sodium nitrate calculated in Step 1 to find the amount of copper(II) nitrate that reacted.

Let's proceed with the calculations based on the provided information.